(x^-3/2y^7/2)^-3/2

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Solution for (x^-3/2y^7/2)^-3/2 equation: 


D( x )

x = 0

(((x^-3)/2)*y^7)/2 = 0

x = 0

x = 0

(((x^-3)/2)*y^7)/2 = 0

(((x^-3)/2)*y^7)/2 = 0

1/4*x^-3*y^7 = 0 // : 1/4*y^7

x^-3 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((((x^-3)/2)*y^7)/2)^-3)/2 = 0

32*x^9*y^-21 = 0 // : 32*y^-21

x^9 = 0

x = 0

x in { 0} 

x belongs to the empty set

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